№ 814. Типовые варианты

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from itertools import product

count = 0
for val in product('01234', repeat=3):
    val = "".join(val)
    # Можно использовать val[0] >= val[1] >= val[2]
    if val[0] != '0' and list(val) == sorted(val, reverse=True):
        count += 1

print(count)