№ 802. Демоверсия

67476

 
import string
from itertools import product

# Алфавит из условия
alph = string.printable[:12]

count = 0
for val in product(alph, repeat=5):
    val = "".join(val)
    if val[0] != '0' and val.count('7') == 1 and val.count('9') + val.count('a') + val.count('b') <= 3:
        count += 1

print(count)